preserve xml format 2003-02-21 - By Voytenko, Dimitry
Hi,
Changed order in the result XML shouldn't cause you any problem. This
feature is explicitly defined within XML 1.0 and DOM specifications. Xerces
orders attributes alphabatically for internal purposes. Thus you can't be
sure their order will be preserved.
Thanks,
Dimitry
-----Original Message-----
From: Ramesh Babu [mailto:qqura@(protected)]
Sent: Friday, February 21, 2003 10:53
To: xerces-j-user@(protected)
Subject: preserve xml format
Hi,
I'm reading xml file and parsing thru'
apache Xerces(xerces-1_4_3) DOMParser.
I serialize the xml and I want to save into the file.
my xml,
<?xml version="1.0" encoding="ISO-8859-1"?>
<Root>
<Property key="A" cat="door"/>
</Root>
and my code,
import java.io.*;
import org.w3c.dom.*;
import org.apache.xml.serialize.*;
import org.apache.xerces.parsers.DOMParser;
public class XmlWriter {
private DOMParser domParser;
private String strFileName;
private Document doc;
public XmlWriter(String strFileName) throws
Exception {
try {
this.strFileName = strFileName;
this.domParser = new DOMParser();
domParser.parse(strFileName);
doc = domParser.getDocument();
}
catch(Exception oEx) {
System.out.println("\n XML Parse Error.\n" +
oEx);
throw oEx;
}
}
public String serializeXml() {
StringWriter sw = new StringWriter();
OutputFormat format = new OutputFormat();
format.setIndenting(true);
format.setLineWidth(0);
format.setPreserveSpace(true);
XMLSerializer serializer = new XMLSerializer(sw,
format);
try {
serializer.asDOMSerializer();
serializer.serialize(this.getDocument().getDocumentElement());
} catch (Exception ex) {
System.out.println("[serializeXml()] exception
while serializing" + ex);
}
return sw.toString();
}
public boolean writeXml(String newXml, String
fileToWrite, boolean append) {
try {
BufferedWriter writer = new BufferedWriter( new
FileWriter( fileToWrite, append ) );
writer.write(newXml);
writer.flush();
writer.close();
} catch(Exception ex) {
System.out.println("[writeXml()] Exception while
writing" + ex);
return false;
}
return true;
}
public Document getDocument() {
return(doc);
}
public static void main(String[] args) {
String fileName = args[0];
XmlWriter writer = null;
try {
writer = new XmlWriter(fileName);
String newXml = writer.serializeXml();
writer.writeXml(newXml, fileName + ".test",
false);
} catch (Exception e) {
e.printStackTrace();
}
}
}
After executing, the file it looks like
<Property cat="door" key="A" />
Actually attributes are sorted which I don't want.
How do I preserver the old format of the xml ?
Any API I need to use ? any help ?
Thanks.
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