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preserve xml format

preserve xml format

2003-02-21       - By Ramesh Babu
Reply:     1     2     3     4  

Hi,
I'm reading xml file and parsing thru'
apache Xerces(xerces-1_4_3) DOMParser.
I serialize the xml and I want to save into the file.

my xml,
<?xml version="1.0" encoding="ISO-8859-1"?>
<Root>
    <Property key="A" cat="door"/>
</Root>

and my code,

import java.io.*;
import org.w3c.dom.*;
import org.apache.xml.serialize.*;
import org.apache.xerces.parsers.DOMParser;

public class XmlWriter {
 private DOMParser domParser;
 private String strFileName;
 private Document doc;
 public XmlWriter(String strFileName) throws
Exception {
   try {
     this.strFileName = strFileName;
     this.domParser = new DOMParser();
     domParser.parse(strFileName);
     doc = domParser.getDocument();
   }
   catch(Exception oEx) {
     System.out.println("\n XML Parse Error.\n" +
oEx);
     throw oEx;
   }
 }

 public String serializeXml() {
   StringWriter sw = new StringWriter();
   OutputFormat format = new OutputFormat();
   format.setIndenting(true);
   format.setLineWidth(0);
   format.setPreserveSpace(true);
   XMLSerializer serializer = new XMLSerializer(sw,
format);

   try {
     serializer.asDOMSerializer();
   
serializer.serialize(this.getDocument().getDocumentElement());
   } catch (Exception ex) {
     System.out.println("[serializeXml()] exception
while serializing" + ex);
   }
   return sw.toString();
 }

 public boolean writeXml(String newXml, String
fileToWrite, boolean append) {
   try {
     BufferedWriter writer = new BufferedWriter( new
FileWriter( fileToWrite, append ) );
     writer.write(newXml);
     writer.flush();
     writer.close();
   } catch(Exception ex) {
     System.out.println("[writeXml()] Exception while
writing" + ex);
     return false;
   }
   return true;
 }

 public Document getDocument() {
   return(doc);
 }

 public static void main(String[] args) {
   String fileName = args[0];
   XmlWriter writer = null;
   try {
     writer = new XmlWriter(fileName);
     String newXml = writer.serializeXml();
     writer.writeXml(newXml, fileName + ".test",
false);
   } catch (Exception e) {
     e.printStackTrace();
   }
 }
}
After executing, the file it looks like

<Property cat="door" key="A" />

Actually attributes are sorted which I don't want.

How do I preserver the old format of the xml ?

Any API I need to use ? any help ?

Thanks.

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