question on xml schema validation with xerces 2

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question on xml schema validation with xerces 2

question on xml schema validation with xerces 2

2003-01-09 - By Kiran Bhumana

Reply: 1 2 3

Please enlighten me on this xmlschema Validation using apache
xercesimpl.

I want to validate an xml file based on xmlschema. I did the following,
the following Java class and the simple xml file.

import org.apache.xerces.parsers.SAXParser;
import org.xml.sax.Attributes;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.SAXParseException;
import org.xml.sax.SAXException;
import java.io.IOException;

// A Simple SAX Application
// Extends org.xml.sax.helpers.DefaultHandler
public class BasicSAX extends DefaultHandler {

// Constructor
public BasicSAX (String xmlFile) {
// Create a Xerces DOM Parser
SAXParser parser = new SAXParser();

// Set Content Handler
parser.setContentHandler (this);

// Parse the Document
try {

parser.setFeature("http://xml.org/sax/features/validation", true);
parser.parse(xmlFile);
} catch (SAXException e) {
System.err.println (e);
} catch (IOException e) {
System.err.println (e);
}
}

// Start Element Event Handler
public void startElement (String uri, String local,
String qName, Attributes atts) {
System.out.println (local);
}

// Main Method
public static void main (String[] args) {
BasicSAX basicSAX = new BasicSAX (args[0]);
}
}

<?xml version="1.0"?>
<note xmlns="http://www.w3schools.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.w3schools.com note.xsd"><to>Tove</to>
<from>Jani</from>
<heading>Reminder</heading>
<body>Don't forget me this weekend!</body>
</note>

The following is the output. Did I understand the apache documentation
wrongly or is this a bug ?

C:\Kiran\test>java -cp c:\kiran\test\xercesImpl.jar;c:\kiran\test
BasicSAX note.xml
[Error] note.xml:2:6: Document is invalid: no grammar found.
[Error] note.xml:2:6: Document root element "note", must match DOCTYPE
root "null".
note
to
from
heading
body

Thankyou,
Kiran B.

<html xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:w="urn:schemas
-microsoft-com:office:word" xmlns="http://www.w3.org/TR/REC-html40">

<head>
<meta http-equiv=Content-Type content="text/html; charset=us-ascii">
<meta name=ProgId content=Word.Document>
<meta name=Generator content="Microsoft Word 10">
<meta name=Originator content="Microsoft Word 10">
<link rel=File-List href="cid:filelist.xml@(protected)">

<style>

</style>

</head>

<body lang=EN-US link=blue vlink=purple style='tab-interval:.5in'>

<div class=Section1>

<o:p> </o:p>

Please enlighten me on this xmlschema Validation using
apache xercesimpl.<o:p></o:p>

<o:p> </o:p>

I want to validate an xml file based on xmlschema. I did the
following, the following Java class and the simple xml file.<o:p></o:p>

<o:p> </o:p>

import org.apache.xerces.parsers.SAXParser;<o:p></o:p>

import org.xml.sax.Attributes;<o:p></o:p>

import org.xml.sax.helpers.DefaultHandler;<o:p></o:p>


import org.xml.sax.SAXParseException;<o:p></o:p>

import org.xml.sax.SAXException;<o:p></o:p>

import java.io.IOException;<o:p></o:p>

<o:p> </o:p>

//  A Simple SAX
Application<o:p></o:p>

//  Extends
org.xml.sax.helpers.DefaultHandler<o:p></o:p>

public class BasicSAX extends DefaultHandler {<o:p></o:p>

     
       <o:p></o:p>

     
       //
Constructor<o:p></o:p>

     
       public
BasicSAX (String xmlFile) {<o:p></o:p>

     
             
      //  Create a Xerces DOM Parser<o:p></o:p>

     
             
      SAXParser
parser = new SAXParser();<o:p></o:p>

     
             
      <o:p></o:p>

     
             
      //  Set Content Handler<o:p></o:p>

     
             
      parser.setContentHandler
(this);<o:p></o:p>

<o:p> </o:p>

     
             
      //  Parse the Document         
     <o:p></o:p>

     
             
      try
{<o:p></o:p>

<o:p> </o:p>

     
             
         
parser.setFeature("http://xml.org/sax/features/validation",
true);<o:p></o:p>

     
             
          parser.parse(xmlFile);<o:p><
/o:p>

     
             
      }
catch (SAXException e) {<o:p></o:p>

     
             
             
     System.err.println
(e);<o:p></o:p>

     
             
      }
catch (IOException e) {<o:p></o:p>

           
             
            System
.err.println
(e);<o:p></o:p>

     
             
      }<o:p></o:p>

     
       }<o:p></o:p>

     
       <o:p></o:p>

     
       //  Start Element Event Handler<o:p></o:p>

     
       public
void startElement (String uri, String local,<o:p></o:p>

     
             
      String
qName, Attributes atts)  {<o:p></o:p
>

     
                   System.out.println
(local);      &nbsp
;    <o:p></o:p>

     
       }<o:p></o:p>

     
       <o:p></o:p>

     
       //
Main Method<o:p></o:p>

     
       public
static void main (String[] args) {<o:p></o:p>

     
             
      BasicSAX
basicSAX = new BasicSAX (args[0]);<o:p></o:p>

     
       }<o:p></o:p>

}<o:p></o:p>

<o:p> </o:p>

<?xml version="1.0"?><o:p></o:p>

<note xmlns="http://www.w3schools.com"<o:p></o
:p>

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance
"<o:p></o:p>

xsi:schemaLocation="http://www.w3schools.com
note.xsd"><to>Tove</to><o:p></o:p>

<from>Jani</from><o:p></o:p>

<heading>Reminder</heading><o:p></o:p>

<body>Don't forget me this weekend!</body><o:p><
/o:p>

</note><o:p></o:p>

<o:p> </o:p>

The following is the output. Did I understand the apache documentation wrongly or is this a bug ?<o
:p></o:p>

<o:p> </o:p>

C:\Kiran\test>java -cp c:\kiran\test\xercesImpl.jar;c:
\kiran\test
BasicSAX note.xml<o:p></o:p>

[Error] note.xml:2:6: Document is invalid: no grammar found.
<o:p></o:p>

[Error] note.xml:2:6: Document root element
"note", must match DOCTYPE root "null".<o:p></o:p>

note<o:p></o:p>

to<o:p></o:p>

from<o:p></o:p>

heading<o:p></o:p>

body<o:p></o:p>

<o:p> </o:p>

<o:p> </o:p>

Thankyou,<o:p></o:p>

Kiran B.<o:p></o:p>

<o:p> </o:p>

</div>

</body>

</html>