Node.getNodeValue() problem 2003-10-20 - By Michael Ryan Bannon
Hello,
This might be just a stupid Java problem I'm overlooking.
The snippet below deals with a TEXT_NODE with a String value "and":
============================================
...
// Output the value of a text node.
// This should, and does, output "and".
System.out.println(node.getNodeValue());
// Test the node.
if (node.getNodeValue() == "and")
System.out.println("it worked");
..
============================================
Now, I've confirmed that it's a text node before the snippet. The first
println outputs "and". However, the "if" statement is false, so I never see
"it worked". How is this possible?
This seems so trivial...what am I missing?
Thanks in advance,
Ryan
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<DIV><FONT face=Arial size=2>Hello,</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>This might be just a stupid Java problem I'm
overlooking.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>The snippet below deals with a TEXT_NODE with a
String value "and"</FONT><FONT face=Arial size=2>:</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial
size=2>============================================</FONT></DIV>
<DIV><FONT face=Arial size=2>...</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>// Output the value of a text node.</FONT></DIV>
<DIV><FONT face=Arial size=2>// This should, and does, output
"and".</FONT></DIV>
<DIV><FONT face=Arial
size=2>System.out.println(node.getNodeValue());</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>// Test the node.</FONT></DIV>
<DIV><FONT face=Arial size=2>if (node.getNodeValue() == "and")</FONT></DIV>
<DIV><FONT face=Arial size=2> System.out.println("it
worked");</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>..</FONT></DIV>
<DIV><FONT face=Arial
size=2>============================================</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Now, I've confirmed that it's a text node before
the snippet. The first println outputs "and". However, the "if"
statement is false, so I never see "it worked". How is this
possible?</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>This seems so trivial...what am I
missing?</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Thanks in advance,</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Ryan</FONT></DIV></BODY></HTML>
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