examining XML schema attributes 2003-07-24 - By Martin Lambert
Hi,
I am trying to examine schema attribute definintions using Xerces. I am able
to retrieve information about attributes that includes an attribute name, its
type name and whether it is required.
However I want to retrieve more detailed information about the attribute's type
. For example, given the type definition below I would like to retrieve the
values that make up the enumeration i.e.
1,2,3,4,5. I can't seem to work out the correct approach to retrieving this
information. I would also like to know how this would work for a type with
restrictions like 'negative integer'.
I have also included my code to highlight how I have been trying to approach
this problem.
<simpleType name="testType">
<restriction base="integer">
<enumeration value="1"/>
<enumeration value="2"/>
<enumeration value="3"/>
<enumeration value="4"/>
<enumeration value="5"/>
</restriction>
</simpleType>
<complexType name="classType">
<sequence>
<element name="template" type="templateType" maxOccurs="unbounded"/>
</sequence>
<attribute name="matches" type="testType" use="required"/>
</complexType>
Where element is an instance of 'XSElementDeclaration':
XSTypeDefinition elementTypeDef = element.getTypeDefinition();
XSObjectList attributeUses = ((XSComplexTypeDefinition)elementTypeDef)
.getAttributeUses();
for(int attrUseIdx=0; attrUseIdx < attributeUses.getLength(); attrUseIdx++)
{
XSAttributeUse attributeUse = (XSAttributeUse)attributeUses.item
(attrUseIdx);
XSAttributeDeclaration attribute = attributeUse.getAttrDeclaration(
);
XSSimpleTypeDefinition attributeType = attribute.getTypeDefinition(
);
System.out.println(attribute.getName() + ", required? " +
attributeUse.getRequired() +
", bounded? " + attributeType.getBounded() + ", finite? " +
attributeType.getFinite() +
", numeric? " + attributeType.getNumeric() + ", type: " +
attributeType.getName() +
", constraint value: " + attribute.getConstraintValue() + ",
enumeration" attributeType);
}
Hope there is a straightforward answer to this.
Cheers,
Martin.
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